216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.
Calculate the mass of aluminum used.
(Specific heat of aluminum = 0.90 J ∙ º C-1 ∙ g-1)

12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.