A rigid tank that contains 2 kg of N2 at 25°C and 550 kPa is connected to another rigid tank that contains 4 kg of O2 at 25°C and 150 kPa. The valve connecting the two tanks is opened, and the two gases are allowed to mix. If the final mixture temperature is 25°C, determine the volume of each tank and the final mixture pressure.

The volume in the first tank = 0.32

The volume in the second tank = 2.066

The  final pressure of the mixture = 203.64 K pa

Explanation:

First Tank

Mass = 2 kg

Pressure = 550 k pa

Temperature = 25 °c = 298 K

Gas constant for nitrogen = 0.297

From the ideal gas equation

P V = m R T

550 × V = 2 × 0.297 × 298

V = 0.32

This is the volume in the first tank.

Second tank

Mass =  4 kg

Pressure = 150 K pa

Temperature = 25 °c = 298 K

Gas constant for oxygen = 0.26  

From the ideal gas equation

P V = m R T

150 × V = 4 × 0.26 × 298

V = 2.066

This is the volume in the second tank.

This is the iso thermal mixing. i.e.

----- (1)

Put this value in equation (1)

× 2.386 =  550 × 0.32 + 150 × 2.066

= 203.64 K pa

Therefore the  final pressure of the mixture = 203.64 K pa

law of conservation of matter

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.