A balloon is filled with 35L of helium in the morning when the temperature is 20C. By noon the temperature has risen to 45C. What is the new volume of the balloon?

38L

Explanation:

Initial volume of helium V1 = 35 L

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

(20°C + 273 = 293K)

New volume V2 = ?

New Temperature T2 = 45°C

(45°C + 273 = 318K)

Since, volume and temperature are involved while pressure is constant, apply the formula for Charles' Law:

(V1/T1) = (V2/T2)

35L/293K = V2/318K

0.119 = V2/318K

To get V2, cross multiply

V2 = 0.119 x 318

V2 = 38L

Thus, the new volume of the balloon is 38 liters

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml