How many moles of aluminum oxide are in a sample with a mass of 204

(204 g)/(101.96 g/mol) = 2.001 mol. 2(2.001) = 4.002 moles of aluminium in the sample

Explanation:

108 g

Explanation:

The molar mass of aluminium is 26.98 g/mol; the molar mass of (atomic) oxygen is 16.00 g/mol.

1 mole of Al₂O₃ therefore has a mass of 2(26.98) + 3(16.00) = 101.96 g.

Divide this into the given mass, to find the number of moles here:

(204 g)/(101.96 g/mol) = 2.001 mol.

There are 2 moles of aluminium per mole of aluminium oxide, so there are

2(2.001) = 4.002 moles of aluminium in the sample.

Then there are (4.002 mol)(26.98 g/mol) = 107.97 g of Al. Since the given mass has only 3 significant figures, round this answer to 108 g.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

pv=nrt

explanation: