A party balloon was inside a store where the temperature was 27 °C. It had a volume of 2.3 L. The balloon was
taken out of the store, where the temperature outside is -3 °C. What is the volume of the balloon now?

2.07L

Explanation:

Data obtained from the question include:

T1 (initial temperature) = 27 °C = 27 + 273 = 300K

V1 (initial volume) = 2.3 L

T2 (final temperature) = - 3 °C = - 3 + 273 = 270K

V2 (final volume) =?

Using V1/T1 = V2/T2, the final volume of the balloon can be obtained as follow:

V1/T1 = V2/T2

2.3/300 = V2/270

Cross multiply to express in linear form.

300 x V2 = 2.3 x 270

Divide both side by 300

V2 = (2.3 x 270)/300

V2 = 2.07L

Therefore, the new volume of the balloon is 2.07L

answer: mercury

explanation:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.