The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appearance of Br2 is M s-1. The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appearance of Br2 is M s-1.
a. 0.0700
b. 1.28
c. 0.0196
d. 0.280
e. 0.374
Answers: 2
is 
![-\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2](/tpl/images/0573/9318/b52fb.png)
= ![\frac{1d[H_2]}{dt}](/tpl/images/0573/9318/06e14.png)
![\frac{1d[Br_2]}{dt}](/tpl/images/0573/9318/f0ecb.png)
![-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}](/tpl/images/0573/9318/40849.png)
![-\frac{1d[HBr]}{dt}=0.140Ms^{-1}](/tpl/images/0573/9318/2b756.png)
![\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}](/tpl/images/0573/9318/cf50e.png)
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The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1...
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