How many grams HBr will be produced from 0.100 moles bromine reacted with excess hydrogen?

16.18 g HBr

Explanation:

We are given;

0.100 moles of Bromine

We need to determine the amount of HBr produced when bromine reacts with hydrogen;

First, we write the equation for the reaction;

H₂(g) + Br₂(l) → 2HBr

From the equation;

1 mole of bromine reacts with hydrogen to form 2 moles of HBr

Therefore;

Moles of HBr = 2 × moles of Bromine

                       = 2 × 0.100 moles

                        = 0.200 moles

Secondly, we determine the mass of HBr produced

Mass = Number of moles × molar mass

Molar mass of HBr = 80.91 g/mol

Thus;

Mass of HBr = 0.200 moles × 80.91 g/mol

                     = 16.182 g

                      = 16.18 g

Therefore, the mass of HBr is 16.18 g