A simple of helium measuring 6L was kept at a pressure is of 1.5 atm ,if pressure is doubled what would be its new volume ?

3L

Explanation:

The following data were obtained from the question:

V1 (original volume) = 6L

P1 (original pressure) = 1.5 atm

P2 (new pressure) = 2 x P1 ( since the new pressure is doubled)

P2 = 2 x 1.5

P2 = 3 atm

V2 (new volume) =?

Using the Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

1.5 x 6 = 3 x V2

Divide both side by 3

V2 = (1.5 x 6)/3

V2 = 3L

From our calculations, the new volume will be half the original volume and this will be 3L

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: