•You have 560. mL of aluminum hydroxide, with a molarity of 0.0300 M. When mixed with 871 mL of hydrochloric acid, what is the molarity (M) of the acidic solution?
•How many liters of 0.488 M H3PO4 are produced with 35.1 mL of 0.320 M of Ca(OH)2 ?

For 1: The molarity of acidic solution is 0.579 M

For 2: The volume of acidic solution is 0.0153 L

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid

are the n-factor, molarity and volume of base

We are given:

Putting values in above equation, we get:

Hence, the molarity of acidic solution is 0.579 M

We are given:

Putting values in above equation, we get:

Hence, the volume of acidic solution is 0.0153 L

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