How many moles of C3H8 contain 9.25x10^24 molecules of C3H8?

15.4

Explanation:

Using Avogadro's Number we have a direct ratio.

6.022

×

10

23

Molecules/mole.

Moles =

9.25

×

10

24

6.022

×

10

23

Moles =

15.4

15.37 moles

Explanation:

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules.

This simply means that 1 mole of C3H8 contains 6.02x10^23 molecules.

Now if 1 mole of C3H8 contains 6.02x10^23 molecules,

Therefore Xmol of C3H8 will contain 9.25x10^24 molecules i.e

Xmol of C3H8 = 9.25x10^24/6.02x10^23

Xmol of C3H8 = 15.37 moles

Therefore, 15.37 moles of C3H8 contains 9.25x10^24 molecules

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24