What is the pOH concentration of a .0768 M NaOH solution?

1.2

Explanation:

pOH is the negative logarithm of hydroxide ion concentration in the solution.

Thus, pOH is expressed as

pH = - log(OH-)

NaOH(aq) ---> Na(aq) + OH-(aq)

The alkali ionizes to give hydroxide ion OH- as the only negative ion. Hence, the concentration of OH- is also 0.0768

So, pOH = - log(0 .0768)

pH = -(-1.15)

pH = 1.15 (since the two minus signs will cancel out)

Round the pOH value to the nearest tenth as 1.2

Thus, the pOH concentration of 0 .0768 NaOH solution is 1.2 (highly concentrated)

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explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)