Compound W, C6H11Cl, undergoes base-promoted E2 elimination to form a single alkene Y. Under similar reaction conditions X, C6H11Br, affords Y and an isomeric alkene. Catalytic hydrogenation of Y produces methylcyclopentane. W readily undergoes an SN2 reaction with sodium iodide in acetone. X does not undergo a similar SN2 reaction. What are the structures of W and X

; The structures of both compounds are shown in the attached image.

Explanation:

First, compound W has the molecular formula C6H11Cl, it is observed that it does not have double bonds. removal of E2 produces compound Y, which is an alkene, which is hydrogenated and produces a methylcyclopentane.

Compound W is an alkyl halide that undergoes an SN1 reaction with sodium iodide in the presence of acetone forming the corresponding iodine compound.

while compound X is a tertiary alkyl halide, it is sterically restricted to undergo SN2 reactions.

answer : a model is often used to explain and make things easier to understand when any scientific topic needs to be demonstrated and explained.

as in this case where a scientist wants to use a model to present the results of his detailed scientific investigation. he should do it as it will him to make the audience understand the concept in a much better way. also, it can be changed according to new scientific understandings.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.