Base your answer on the information below and on your knowledge of chemistry.

A NaOH(aq) solution with a pH value of 13 is used to determine the molarity of an HCl(aq) solution. A 10.0-mL sample of the HCl(aq) is exactly neutralized by 16.0 mL of 0.100 M NaOH(aq). During this laboratory activity, appropriate safety equipment was used and safety procedures were followed.

Determine the pH value of a solution that has a H+(aq) ion concentration 10 times greater than the original NaOH(aq) solution.

1. c = 0.16 mol·L⁻¹; 2. pH = 12

Explanation:

HCl + NaOH ⟶NaCl + H₂O

1. Concentration of HCl

(a)Moles of NaOH

(b) Moles of HCl

The molar ratio is 1 mol HCl:1 mol NaOH.  

(c) Molar concentration of HCl

2. Hydronium ion in NaOH solution

In the original solution, pH = 13.

[H₃O⁺] = 10⁻¹³ mol·L⁻¹

At 10 times the concentration of hydronium ion

[H₃O⁺] = 10 × 10⁻¹³ mol·L⁻¹ = 10⁻¹² mol·L⁻¹

pH = -log[H₃O⁺] = -log(10⁻¹²) = 12

The pH decreases by one unit when the hydronium ion increases tenfold.

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the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

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