In order to determine the identity of a particular lanthanide metal (M), a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl3, and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3)2 solution. The two half-reactions are as follows:
M(s)  M3+(aq) + 3e–
Cu2+(aq) + 2e– Cu(s)
The potential measured across the cell is 2.70 V. What is the identity of the metal?
Reduction Half-Reaction
E° (V)
Cu2+(aq) + 2e– Cu(s)
0.34
Ce3+(aq) + 3e– Ce(s)
–2.336
Tm3+(aq) + 3e– Tm(s)
–2.319
Eu3+(aq) + 3e– Eu(s)
–1.991
Gd3+(aq) + 3e– Gd(s)
–2.279
Sm3+(aq) + 3e– Sm(s)
–2.304
Tm
Gd
Ce
Eu
Sm
Answers: 1
Chemistry, 21.06.2019 20:30, Cooldude3966
As you move from right to left on the periodic table the atomic radius fill in the blank
Answers: 2
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