A researcher studying the nutritional value of a new candy places a 4.70 g 4.70 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.41 ∘ C. 2.41 ∘C. If the heat capacity of the calorimeter is 43.90 kJ ⋅ K − 1 , 43.90 kJ⋅K−1, how many nutritional Calories are there per gram of the candy?

Answer : The nutritional Calories per gram of the candy are, 5.36 calories

Explanation :

First we have to calculate the amount of heat.

where,

q = heat = ?

c = specific heat =

= change in temperature =

Now put all the given values in the above formula, we get:

Now we have to calculate the heat for per gram of sample.

Heat =

Now we have to calculate the heat in terms of calories.

As, 1 nutritional Calories = 1000 calories

and, 1 calories = 4.2 J

As, 4.2 J = 1 calories

So, 22510 J =

Therefore, the nutritional Calories per gram of the candy are, 5.36 calories

l dont know l am s sorry

i think the answer is terrae but not 100 percent sure. ▓▬▬ §