Hat set of reaction conditions would favor an SN2 reaction on 2-bromo-3-methylbutane? weak nucleophile in a protic solvent weak nucleophile in an aprotic solvent strong nucleophile in an aprotic solvent strong nucleophile in a protic solvent

Strong nucleophile in an aprotic solvent favors reaction on 2-bromo-3-methylbutane.

Explanation:

reaction proceeds through a tetragonal bipyramidal transition state where incoming nucleophile and leaving group simultaneously enter and leave the nucleophilic center.If weak nucleophile is used for nucleophilic substitution then  detachment of leaving group can take place earlier to attack by nucleophile favoring mechanism.If protic solvent is used then, it will make H-bonding with nucleophile. Therefore nucleophilicity is somewhat reduced and the substrate gets enough time to produce carbocation before it gets attacked by nucleophile.

So, strong nucleophile in an aprotic solvent favors reaction on 2-bromo-3-methylbutane.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !