A sample of a gas at room temperature occupies a volume of 29.0 L at a pressure of 562 torr . If the pressure changes to 2810 torr , with no change in the temperature or moles of gas, what is the new volume, V2?

The new volume will be 5.80 L

Explanation:

Step 1: Data given

The initial volume = 29.0 L

The initial pressure = 562 torr = 562 /760 atm = 0.739474 atm

The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm

The temperature and number of moles will not change

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒With P1 = the initial pressure = 0.739474 atm

⇒with V1 = the initial volume = 29.0 L

⇒with P2 = the increased pressure = 3.697368 atm

⇒with V2 = The new volume = TO BE DETERMINED

0.739474 atm * 29.0 L = 3.697368 atm * V2

V2 = 5.80 L

OR

562 torr * 29.0 L = 2810 torr * V2

V2 = 5.80 L

The new volume will be 5.80 L

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.