A liquid is exposed to infrared radiation with a wavelength of 6.92 × 10 − 4 cm. 6.92×10−4 cm. Assume that all the radiation is absorbed and converted to heat. How many photons are required for the liquid to absorb 58.28 J 58.28 J of heat?

The no. of photons required for total heat absorbed of 58.28 J is N = 20.28  × Photons

Explanation:

Wave length = 6.92 × cm =  6.92 × m

Total Energy E = 58.28 J

Energy content of a single photon is given by

where h = plank constant = 6.626 × J - s

c = speed of the light = 3 ×

So Energy content of a single photon is

×

E = 2.87 × J

No. of photons required is

N = ×

N = 20.28  × Photons

This is the no. of photons required for total heat absorbed of 58.28 J