Chemistry, 04.02.2020 19:50 deduran

In which isotope is the strong nuclear force not strong enough to balance electrostatic forces between protons? . a. carbon-13. b. hydrogen-2. c. neon-21. d. uranium-238

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Answer from: liljohnsjs218

Answer;

D. uranium-238

Explanation;In uranium-238 the strong nuclear force not strong enough to balance electrostatic forces between protons. Therefore, Uranium-238 atom is not stable and thus it is radioactive. For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently. An unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stabilityUranium-238 is an example of such atom, which may undergo decay to achieve stability.

Answer from: kayliej02

The correct answer is option D, that is, uranium-238.

Explanation:

In all the nuclei above atomic number 83, the nuclear force is not adequately strong to poise the electrostatic repulsion among the protons. The nuclei like carbon-13, hydrogen-2 and neon-21 are all stable. However, the elements like uranium-238 are radioactive and exhibit a half-life of approximately 4.5 billion years.

In order for the atom to be stable, it should exhibit a sufficient amount of binding energy to keep its nucleus with each other perpetually. An atom that is not stable is devoid of enough amount of binding energy to sustain its nucleus perpetually, and therefore, goes through decay in order to attain stability. Uranium-238 is an illustration of such an atom that may go through decay to attain stability.

Answer from: Quest

Alpha particles have positive charge, beta particles have negative charge, and answer 4 just doesn’t make sense. thus, you are left with only one possible answer.

Answer from: Quest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$