Chemistry, 29.03.2020 05:08 yeinp9353

60.0 mL of 0.100 M Ca(OH)2 solution is mixed with 50.0 mL of 0.100 M HNO3. Calculate the volume of 0.100 M H2SO4 needed to neutralize the resulting mixture.

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The volume of 0.100 M H₂SO₄ needed to neutralize the resulting mixture containing an excess of 10 ml of 0.100 M Ca(OH)₂ is 10 ml of 0.100 M H₂SO₄ .

Explanation:

Ca(OH)₂ + HNO₃ = Ca(NO₃)₂ + H₂O

From the above reaction;

1 mole of Ca(OH)₂ is required to neutralize 1 mole of HNO₃ also

0.1 mole of Ca(OH)₂ will be required to neutralize 0.1 mole of HNO₃

Since there is 60 ml of 0.100 M Ca(OH)₂ and 50.0 mL of 0.100 M HNO₃, then on completion of neutralization, there will be 10 ml of 0.100 M Ca(OH)₂ left to be consumed

When H₂SO₄ is added to the solution, the reaction will be as follows;

Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O

Therefore we have;

1 mole of H₂SO₄ is required to completely react with 1 mole of Ca(OH)₂

Hence,

0.1 mole of H₂SO₄ will completely react with 0.1 mole of Ca(OH)₂

Therefore the volume of 0.100 M H₂SO₄ required to neutralize the resulting mixture containing an excess of 10 ml of 0.100 M Ca(OH)₂ is 10 ml

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For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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60.0 mL of 0.100 M Ca(OH)2 solution is mixed with 50.0 mL of 0.100 M HNO3. Calculate the volume of 0...