A solution of carbon tetrachloride and carbon disulfide containing 50% by weight of each is to be continuously distilled at a rate of 5000 kg/h.
(a) Determine the concentration of the mixture in terms of mole fractions. (b) Determine the average molecular weight of the mixture.
(c) Calculate the feed rate in kmol/h.

(a) CS₂ = 0.331, CCl₄ = 0.669; (b) 102 g/mol; (c) 49.1 kmol/h

Explanation:

Assume 5000 kg of mixture.

(a) Mole fractions

(i) Mass of each compound

Mass of CCl₄ = 2500 kg

Mass of CS₂ = 2500 kg

(ii) Moles of each compound

(iii) Mole fractions

Total moles = 16.3 kmol + 32.8 kmol = 49.1 kmol

The major component is usually called the solvent — Component 1 —carbon disulfide.

(c) Average molar mass

The average molar mass is the weighted molar mass of each component.

(d) Feed rate