Give the ground-state electron configuration for silicon. Express the complete electron configuration using superscripts where appropriate. For example, the configuration for Li would be entered as 1s^22s^1.Give the actual ground-state electron configuration for copper. Express the electron configuration using superscripts where appropriate. For example, the configuration for Li would be entered as 1s^22s^1.

Si 1s^2 2s^2 2p^6 3s^2 3p^2

Co (actual) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^1

Co (expected) 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^9

i'd be careful with Copper. i listed the actual e- configuration for an element and lost points cause they were looking for the expected e- configuration

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g