A 250 ml solution of 2.0 M NaOH is diluted to 1.0 liter. What is the final concentration of the solution?

Diluted concentration is 0.5M

Explanation:

Let's solve this with rules of three, although there is a formula to see it easier

In 1000 mL (1L), we have 2 moles of NaOH

In 250 mL we must have (250 . 2) / 1000 = 0.5 moles of NaOH

These moles will be also in 1 L of the final volume of the diluted solution

More easy:

1 L of solution has 0.5 moles of NaOH

Then, molarity is 0.5 M

The formula is: Concentrated M . Conc. volume = Diluted M . Diluted volume

2 M . 0.250L = 1L . Diluted M

0.5M = Diluted M

The final concentration of the solution is 0.500 M

Explanation:

Step 1: data given

Initial volume = 250 mL = 0.250 L

Molarity NaOH = 2.0 M

The volume is diluted to 1.0 L

Step 2: Calculate the final concentration of the solution

C1*V1 = C2*V2

⇒with C1 = the initial concentration of NaOH = 2.0 M

⇒with V1 = the initial volume = 250 mL = 0.250 L

⇒with C2 = the final concentration of the solution = TO BE DETERMINED

⇒with v2 = the volume of the diluted solution = 1.0 L

2.0 M * 0.250 L = C2 * 1.0 L

C2 = 2.0* 0.250

C2 = 0.500 M

The final concentration of the solution is 0.500 M

idk

explanation: