For the reaction NH4NO3 (s) → N2O (g) + 2H2O (l), You decompose 1 mole of NH4NO3 and only get 0.7 moles of N20. What is the percent yield?
90%
25%
65%
70%

70% is the percent yield

Explanation:

First of all, we work with the stoichiometry of the decomposition:

NH₄NO₃ (s) → N₂O (g) + 2H₂O (l)

1 mol of ammonium nitrate can produce 1 mol of nitrogen oxide.

This, will happen with the 100% yield reaction.

To determine the percent yield we do:

(moles produced / theoretical yield) . 100 =

(0.7 moles / 1 mol) . 100 = 70%