Predict the rate of change in the concentration of N2O over this time interval. In other words, what is Δ[N2O]/Δt?

A) Rate = -k [N₂O]²

B) Rate = 0.0031 M/s

C) Rate of change in the concentration of N₂O = -0.0062 M/s

Explanation:

2N₂O(g)-->2N₂(g)+O₂(g)

A) To first guess what the rate of reaction light be

Rate = -k [N₂O]² (minus sign because the concentration of reactant is reducing)

B) Rate of reaction = (Change in concentration of reactants)/time

It is also equal to (Change in concentration of products too)/time.

So,

Rate of reaction = (Change in concentration of O₂)/time

Change in concentration of O₂ = (0.019/0.47) - 0 = 0.0404 M

Time = 13.0 s

Rate of reaction = (0.0404/13) = 0.00311 M/s = 0.0031 M/s to 2 s.f.

C) Rate of change in the concentration of N2O over this time interval.

(1/2) -[Δ(N₂O)/Δt] = (Δ(O₂)/Δt)

[Δ(N₂O)/Δt] = -2 × (Δ(O₂)/Δt)

[Δ(N₂O)/Δt] = -2 × 0.0031 = -0.0062 M/s

Hope this Helps!!!

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o