What is the formula of the ion formed when phosphorus achieves a noble-gas electron configuration?

a. p3

b. p2

c. p2-

d. p3-

d. p3-

Explanation:

Phosphorus has fifteen electrons in its orbitals and five electrons in its outermost shell. An atom is said to have noble gas configuration when it has eight electron in its outermost shell.

In order to have eight electrons in its outermost shell, phosphorus must accept three electrons and form an ion of the sort P^3-. This ion now has eighteen electrons (argon configuration) and eight electrons in the outermost shell.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

what does the table look like