Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is the concentration of Cu2+ ions in the solution after the addition of NH3? The Kf for Cu(NH3)42+ is 1.7x1013.

M

Explanation:

Concentration of = 0.020 M

Constructing an ICE table;we have:

Initial (M)             0.020          0.40                        0

Change (M)         -  x                - 4 x                       x

Equilibrium (M)  0.020 -x        0.40 - 4 x              x

Given that:

Since x is so small; 0.40 -4x = 0.40

Then:

M

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