A gaseous mixture is composed of 1.5 moles of He, 2.5 moles of N2 and an unknown number of moles of He. The mixture is contained within a 20-liter vessel. If the partial pressure of the N2 is 10 atm, what is the temperature of the mixture in degrees Kelvin, ˚K? R= 0.0821 L x atm/mol x ˚K.

Answer : The temperature of the mixture will be, 974.4 K

Explanation :

Using ideal gas equation:

where,

P = Pressure of gas = 10 atm

V = Volume of gas = 20 L

n = number of moles  = 2.5 mole

R = Gas constant =

T = Temperature of gas = ?

Now put all the given values in above equation, we get:

The temperature of the mixture will be same as the temperature of gas.

Therefore, the temperature of the mixture will be, 974.4 K