∆G° for the reaction of nitrogen with hydrogen to produce ammonia (see balanced chemical equation below) has a value of -33.3 kJ/mol. What will be ∆G for this reaction at 25° C if the reaction is initiated with 125 atm each of N2 and H2 and 2.00 atm NH3(g)? N2(g) + 3H2(g) 2NH3(g)

-0.85KJ

Explanation:

Given N2(g) + H2(g) <--->2NH3(g)

Kp =[ P(NH3)]²/[P(H2)]³[P(N2)]

Where P is the pressure of the gas

P(H2)b= P(N2) = 125atm

P(NH3) = 200atm

Kp = 2²/(125)³(125)

Kp = 2.048 ×10^-6

∆G = -RTlnKp

R =0.008314 J/Kmol

T = 25 +273/= 298k

= 8.314 ×10^-3 × 298 × ln(2.048 ×10^-6)

= -0.008314 × 298 × (-13.099)

= 32.45KJ

∆G = ∆G° + RTlnKp

∆G = -33.3 + 32.45

∆G = -0.85KJ or -850J

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.  

i believe the answer is 5,000