What is the solubility of KCL at 5 degrees celsius

The Solubility of KCl at 5 degrees Celsius is 28 g/100 ml of H2O.

Explanation:

Solubility is defined as the maximum amount of a substance that dissolves in a given amount of solvent at a specific temperature. The temperature and pressure are the two factors that affect solubility.

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The solubility is calculated by dividing the mass of the compound by the mass of the solvent and multiply by 100 g to calculate the solubility  in g/ 100 g.

Hence, the solubilty of KCL at 5 degree celsius is 28 g/ 100 ml of H2O.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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