In acid dilution problem, describe how you created 500 ml of a 5.5 M HCl solution from the 11.6 M stock solution. Show your calculations and give details about the equipment used, which solutions you mixed together, and amounts of each.

237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

where,

= molarity of stock solution = 11.6 M

= volume of stock solution = ?

= molarity of dilute solution = 5.5 M

= volume of dilute solution = 500 ml

Thus 237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution

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