Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8)(C10H8). When 1.025 gg of naphthalene is burned in a bomb calorimeter, the temperature rises from 24.25 ∘C∘C to 32.33 ∘C Find ΔErxn for the combustion of naphthalene. The heat capacity of the calorimeter, determined in separate experiment, is 5.11kJ/∘C .

The enthalpy of the reaction is -5167.71 kJ

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

where,

q = heat absorbed

c = heat capacity of calorimeter = 5.11 kJ/°C

= change in temperature =

Putting values in above equation, we get:

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

Given mass of naphthalene = 1.025 g

Molar mass of naphthalene = 128.2 g/mol

Putting values in above equation, we get:

To calculate the enthalpy change of the reaction, we use the equation:

where,

q = amount of heat released = -41.29 kJ

n = number of moles of naphthalene = 0.00799 moles

= enthalpy change of the reaction

Putting values in above equation, we get:

Hence, the enthalpy of the reaction is -5167.71 kJ

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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