(a) 4.64 x 1024 atoms Bi into grams

1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi

Explanation:

Let's do the required conversions:

1 mol of atoms has 6.02×10²³ atoms

Bi → 1 mol of bismuth weighs 208.98 grams

Let's do the rules of three:

6.02×10²³ atoms are the amount of 1 mol of Bi

4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles

1 mol of Bi weighs 208.98 g

7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.