How many grams are there in 2.00 moles of sulfuric acid

196g

Explanation:

We'll begin by obtaining the molar mass of sulphuric acid as shown below:

Molar Mass of sulphuric acid(H2SO4) = (2x1) + 32 + (16x4) = 2 + 32 + 64 = 98g/mol

Number of mole of H2SO4 = 2 moles

Mass of H2SO4 =?

Mass = number of mole x molar Mass

Mass of H2SO4 = 2 x 98 = 196g

Therefore, 2moles of sulphuric acid contains 196g of sulphuric acid

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

it is the most commonly accepted one