The concentration of SO32- in a solution is determined by titration with a 0.1355 M permanganate solution. The balanced net ionic equation for the reaction is: 2MnO4-(aq) + 5SO32-(aq) + 6H3O+(aq) 2Mn2+(aq) + 5SO42-(aq) + 9H2O(l) (a) If 23.89 mL of the 0.1355 M permanganate solution are needed to react completely with 25.00 mL of the SO32- solution, what is the concentration of the SO32- solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Mn2+ ion is transferred to a volumetric flask and diluted to 400. mL. What is the concentration of Mn2+ in the diluted solution? M

a) 0.3237M of the SO₃⁻ solution.

b) Permanganate solution

c) 0.008093M

Explanation:

a) Based in the reaction, 2 moles of MnO₄⁻ react with 5 moles of SO₃⁻. Moles of permanganate used in titration are:

0.02389L×0.1355mol/L = 0.003237moles of MnO₄⁻. The moles of SO₃⁻ are:

0.003237moles of MnO₄⁻ × (5 moles of SO₃⁻ / 2 moles of MnO₄⁻) = 0.008093 moles of SO₃⁻

As volume of the solution is 25.00mL, the concentration of the solution is:

0.008093 moles of SO₃⁻ / 0.02500L = 0.3237M of the SO₃⁻ solution.

b) In a titration, the solution that is in the buret (Titrant), is the solution of known concentration, for the problem, permanganate solution

c) The moles of the Mn²⁺ solution are the same of MnO₄⁻. That is:

0.003237moles. As the volume of the new solution is 400mL, the concentration of the solution is:

[ Mn²⁺] = 0.003237moles / 0.400L = 0.008093M

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.