Calculate the volume of 0.0500 M H2SO4 solution required to completely react with 20.0 mL of 1.00 x 10-3 M NaOH.

vol 0.05M H₂SO₄ = 0.200 ml

Explanation:

H₂SO₄ + 2NaOH => NaCl + 2 H₂O

moles = Molarity X Volume

From balanced equation 1 mole H₂SO₄ neutralizes 2 moles NaOH.

Using neutralization equation

Moles NaOH neutralized = 2 x Moles H₂SO₄ used

∴ 1(Molarity x Volume Base) = 2(Molarity x Volume Acid)

=> Volume of Acid needed = Molarity x Volume of Base / 2 x Molarity of Acid

=> Volume of Acid needed = (0.001M x 20 ml) / (2 x 0.05M) = 0.20 ml Acid

we need 0.2 mL of a 0.0500M  H2SO4 solution

Explanation:

Step 1: Data given

Molarity of H2SO4 = 0.0500 M

Volume of NaOH = 20.0 mL = 0.020 L

Molarity of NaOH = 1.00 * 10^-3 M

Step 2: The balanced equation

2NaOH + H2SO4 → Na2SO4 + 2H2O

Step 3: Calculate the volume of H2SO4

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of NaOH = 1.00 * 10^-3 M

⇒with Va = the volume of NaOH = 0.020 L

⇒with a = the coefficent of NaOH = 2

⇒with Cb = the concentration of H2SO4 = 0.0500 M

⇒with Vb = the volume of H2SO4 = TO BE DETERMINED

1*10^-3 * 0.020 = 2*0.0500 * Vb

Vb = 0.0002 L = 0.2 mL

we need 0.2 mL of a 0.0500M  H2SO4 solution

idk

explanation:

dasdad

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.