Ethanol has the chemical formula C2 H6 O . A sample of ethanol contains 164grams of C. How many molecules are in the sample? (4.11E24 molecules C2 H6 O)

We have 8.22 1 C atoms

We have 4.11 1 ethanol molecules

Explanation:

Step 1: Data given

Molecular formula of ethanol =

Mass of C = 164 grams

Molar mass C = 12.01 g/mol

Step 2: Calculate moles C

Moles C = mass C / molar mass C

Moles C = 164 grams / 12.01 g/mol

Moles C = 13.66 moles

Step 3: Calculate molecules of C

Atoms C = moles C number of Avogadro

Atoms C = 13.66 moles 6.02 1 molecules/ mol

Atoms C = 8.22 1 C atoms

Step 4: Calculate molecules in the sample

For 1 mol we have 2 moles C

For 13.66 moles C we have 13.66/ 2 = 6.83 moles

Molecules = 6.83 moles 6.02 1 = 4.11 1 molecules.

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