For a given reaction, ΔH = +35.5 kJ/mol and ΔS = +83.6 J/Kmol. The reaction is spontaneous . Assume that ΔH and ΔS do not vary with temperature.

a) at T > 298 K
b) at T > 425 K
c) at all temperatures
d) at T < 425 K

b) at T > 425 K

Explanation:

∴ ΔG < 0 ⇒ The reaction is spontaneous

∴ ΔG > 0 ⇒ The reaction is not spontaneous

∴ ΔG = 0 ⇒ The equilibrium

∴ ΔH = +35.5 KJ/mol

∴ ΔS = (+83.6 J/K.mol)*(KJ/1000 J) = 0.0836 KJ/K.mol

at T = 298 K:

⇒ ΔG = 35.5 KJ/mol

⇒ ΔG = 35.5 - (298)(0.0836) = 35.5 - 24.913 = 10.587 KJ/mol > 0... No spontaneous

at T = 425 K:

⇒ ΔG = 35.5 - (425)(0.0836) = 35.5 - 35.53 = - 0.03 KJ/mol < 0is spontaneous

The reaction is spontaneous at temperature: T > 425. Choice B.

The mathematical representation of the Gibb's free energy as given below provides a basis for determining if a reaction is spontaneous or not.

The value of the enthalpy and entropy given are;

By setting;

Therefore;

By dividing through by 0.0836; we have;

In essence, the reaction is spontaneous at temperature, T > 425 in which case the Gibb's free energy: ΔG < 0.

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yes it is balanced

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole