On the illustration below, write a caption for discharge zone and for aquifer.

caption for discharge zone: The discharge of water from vegetated soil to the sideby river via seepage

caption for aquifer: The recharging of groundwater by seepage of river water to the aquifer.

We know that water always maintains its level. In the given figure, we can see that up-hill area receive precipitation which runs to the stream as well as perculates through the soil. This perculation allows the growth of plants as well which can be seen in the figure. However, this perculation will also follow the path to reach the river/stream, thus feeding it. This is called water discharge.

By contrast, in the lower part of the figure, one can see that water the river water level is playing a major role in the groundwater recharge process. Precisely, some of the water from stream is moving to the underlying aquifer unsaturated zone. Resultantly, this is increasing the water table. This process is called groundwater recharging.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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