How many miles of co2 are emmited into the atmosphere when 11.6g of c8h18 is burned?

0.816 mole

Explanation:

To solve this problem, first, we need to balance the equation. The balance equation is given below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Next, let us covert 11.6g of C8H18 to moles. This is illustrated below:

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 = 11.6g

Number of mole = Mass /Molar Mass

Number of mole of C8H18 = 11.6/114

Number of mole of C8H18 = 0.102mole.

Now we can easily find the number of mole of CO2 emitted as shown below:

From the balanced equation,

2 moles of C8H18 produced 16 moles of CO2.

Therefore, 0.102mole of C8H18 will produce = (0.102x16)/2 = 0.816mole of CO2.

Therefore, 0.816 mole of CO2 are emitted.

i think it's letter a.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally