Consider this balanced chemical equation: 5SF4 + 2I2O5 = 4IF5 + 5SO2 a. What is the limiting reagent when 4.687 grams SF4 reacts with 6.281 grams I2O5 to produce IF5 and SO2.

The limiting reagent is the SF₄

Explanation:

In order to determine the limiting reagent we convert the mass of the reactants to moles, and then, we work with stoichiometry.

4.687 g / 108.06 g/mol =  0.0433 moles of SF₄

6.281 g / 333.8 g/mol = 0.0188 moles of I₂O₅

The reaction is:  5SF₄ + 2I₂O₅ = 4IF₅ + 5SO₂

Ratio is 5:2. 5 moles of fluoride react with 2 moles of pentoxide

Then, 0.0433 moles of fluoride will react with (0.0433 . 2) / 5 = 0.0173 moles

We have 0.0188 moles of I₂O₅ and we need 0.0173 so there are some moles of pentoxide that remains after the reaction. In conclussion, the limiting reagent is the SF₄. We verify:

2 moles of pentoxide react with 5 moles of SF₄

Therefore, 0.0188 moles of I₂O₅ will react with (0.0188 . 5) / 2 = 0.0470 moles.

As we have 0.0433 moles of SF₄, we do not have enough moles.

pure water does not conduct electricity very well. however, when certain substances are dissolved in water, the solution does conduct electricity. you can make a simple device that shows how well a solution conducts electricity. this device uses a flashlight bulb to indicate how well the solution conducts electricity. the better the solution conducts electricity, the brighter the bulb will glow.

explanation:

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.