A student dissolves 0.0100 mole of an unknown weak base in 100.00 mL water and titrates the
solution with 0.100 MHNO3. After 40.00 mL of 0.100M HNO3 was added, the pH of the resulting solution was 8.00. Calculate Kb
value for the weak base.

The value of for weak base is

Explanation:

We are given:

Moles of unknown weak base = 0.0100 moles

To calculate the number of moles for given molarity, we use the equation:

Molarity of nitric acid = 0.100 M

Volume of solution = 40.0 mL

Putting values in above equation, we get:

The chemical reaction for unknown weak base (BOH) and nitric acid follows the equation:

Initial:          0.0100       0.004        

Final:           0.006          -             0.004

Volume of solution = 100 + 40 = 140 mL = 0.140 L    (Conversion factor:  1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

We are given:

= negative logarithm of acid dissociation constant of formic acid = ?

pH = 8.00

pOH = 14 - pH = 14 - 8 = 6

Putting values in above equation, we get:

We know that:

Hence, the value of for weak base is

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied