The combustion of ethane ( C 2 H 6 ) produces carbon dioxide and steam. 2 C 2 H 6 ( g ) + 7 O 2 ( g ) ⟶ 4 CO 2 ( g ) + 6 H 2 O ( g ) How many moles of CO 2 are produced when 5.90 mol of ethane is burned in an excess of oxygen?

5.90 moles of ethane, C₂H₆, is burned in an excess of oxygen to produce 11.8 moles of CO₂.

Explanation:

To answer the question, we examine the chemical reaction as follows

2C₂H₆ ( g ) + 7O₂ ( g ) ⟶ 4CO₂ ( g ) + 6H₂O ( g )

From the chemical reaction it is seen that 2 moles of ethane, C₂H₆, is required to produce 4 moles of CO₂

This means that 1 mole of C₂H₆, is required to produce 2 moles of CO₂

Since we are asked to find out how many moles of CO 2 are produced when 5.90 moles of ethane is burned in an excess of oxygen and we already know that 1 mole of C₂H₆, is required to produce 2 moles of CO₂, we multiply both the 1 mole of C₂H₆ and the 2 moles of CO₂  by 5.90 to obtain;

(5.90 × 1 mole) of C₂H₆  is required to produce (5.90× 2 moles) of CO₂ or

5.90 moles of C₂H₆  is required to produce 11.8 moles of CO₂.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer