What is the concentration of HNO3 if 9.80×10−2 mol are present in 705 mL of the solution?

The answer to your question is 0.13 M

Explanation:

Data

[HNO₃] = ?

moles of HNO₃ = 9.8 x 10⁻²

volume = 705 ml

Process

1.- Convert volume to milliliters

                 1000 ml 1 L

                    705 ml x

                    x = (705 x 1) / 1000

                    x = 705 / 1000

                    x = 0.75 L

2.- Calculate the molarity

Molarity = moles / volume

Molarity = 9.8 x 10⁻² / 0.75

Molarity = 0.13

the answer is 1 i believe

idk what the question is about