At a certain temperature, 0.780 mol SO 3 0.780 mol SO3 is placed in a 4.00 L 4.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.100 mol O 2 0.100 mol O2 is present. Calculate K c .

0.00297

Explanation:

Moles of   = 0.780 mole

Volume of solution = 4.00 L

Initial concentration of =

Equilibrium concentration of =

The given balanced equilibrium reaction is,

Initial conc.         0.195 M            0 M       0 M

At eqm. conc.     (0.195-2x) M   (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

Given = x = 0.025 M

Thus is 0.00297

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.