When 60.0 g of CH4 reacts with excess O2, the actual yield of CO2 is 112 g. What is the percent yield? CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) Group of answer choices

67.88% is the percent yield.

Explanation:

Moles of methane =

According to reaction,1 mole of methane gives 1 mole of carbon dioxide gas, then 3.75 moles of methane will give :

of carbon dioxide gas

Mass of 3.75 moles of carbon dioxide gas:

3.75 mol × 44 g/mol = 165 g

Theoretical yield of the carbon dioxide gas = 165 g

Experimental yield of the carbon dioxide gas = 112 g

The percentage yield of the reaction :

67.88% is the percent yield.

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