Answers: 2
= 1.5 million years
![[A]=[A_o]\times e^{-\lambda t}](/tpl/images/0553/9905/3c150.png)
![[A]=[A_o]\times ^{-\frac{0.693}{1.5 \text{million years}}\times 6.0\text{million years}}](/tpl/images/0553/9905/65a36.png)
![[A]=0.06254 [A_o]](/tpl/images/0553/9905/b6e49.png)
![[A]=\frac{[A_o]}{2^n}](/tpl/images/0553/9905/45c59.png)
............(1)![0.06254 [A_o]=\frac{[A_o]}{2^n}](/tpl/images/0553/9905/0acff.png)
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