Suppose you have a liquid solution containing two components, acetone and nonane. The boiling point of pure acetone is 56 C and the boiling point of pure nonane is 151 C. Your solution has a mole fraction of component acetone equal to 0.1, and the solution behaves as an ideal solution. What is the boiling point of this solution?

The boiling point is somewhere between 56 and 151 °C

Explanation:

Hello,

In this case, it is possible to compute it via rigorous methods in phase equilibrium by using for example a cubic equation of state to model the vapor phase and a suitable excess Gibbs free energy model for the liquid phase, nonetheless, it is an arduous task. In such a way, since the information about both acetone's and nonane's pure boiling points is given as well as acetone's mole fraction, which points out it is about a binary liquid solution, one could make up the boiling point is somewhere between 56 and 151 °C precising that it should be closer to 151 °C as the mixture is 90% nonane and 10% acetone.

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the answer is a and have a great day