Suppose you wanted to dissolve 294.3g of H2SO4 in 250 mL of H2O.

A. What is the solute? explain

B. What is the solvent? explain

C. What is the molarity of the solution?

Molarity =7.3 M

H₂SO₄ is solute.

Water is solvent.

Explanation:

Given data:

Mass of H₂SO₄ = 294.3 g

Volume of water = 250 mL

Which is solute = ?

Which is solvent = ?

What is molarity = ?

Solution:

Solute and solvent.

Solute is present in less quantity as compared to the solvent. It is always dissolved by the solvent. In given question water is present in large amount so it is solvent. While H₂SO₄ is solute.

If we convert the g of H₂SO₄ into volume,

d = m/v

1.83 g/cm³ = 294.3 g / v

v = 294.3 g/ 1.83 g/cm³

v = 160.82 cm³ or 160.82 mL

SO water is present in large amount.

Molarity:

Molarity = number of moles of solute / volume of solution in L

Volume of solution = 160.82 mL + 250 mL

Volume of solution = 410.82 mL   (410.82 /1000 =0.411 L)

Number of moles of solute:

Number of moles = mass/ molar mass

Number of moles = 294.3 g/ 98.1 g/mol

Number of moles = 3 mol

Now we will determine the molarity:

Molarity = 3 mol / 0.411 L

Molarity =7.3 M

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