subject
Chemistry, 18.03.2020 20:07 josebienka

Specific Heat of Water = 4.186
J
g°C

Specific Heat of Ice = 2.00
J
g°C

Molar Heat of Fusion = 6030
J
mol

Molar Heat of Vaporization = 40790
J
mol
You take an ice cube (mass = 18g) from the freezer (T = -10°C) and place it on the table. Later that day, you notice a puddle of water on the table that has reached ambient room temperature (20°C). How much heat must have been absorbed to make this happen?

A) 1867.0 J
B) 2260.4 J
C) 7897.0 J
D) 42657.0 J

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Answers: 3

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You know the right answer?
Specific Heat of Water = 4.186
J
g°C

Specific Heat of Ice = 2.00
J

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